9. Let f(x) = 3x2 - 6x - 9. a. Algebraically (by hand) find the vertex. (5pt's 2/5 X = = 6 29 2 (3 ) f ( - $ ) = 2 1 - 1 ) 2 - 4 ( - 1) = 8 3 (112 - Q (1) - 9 = 0 verlex (- 1,95 lieu anotteups to more 2/ 3 b. Write f (x) in vertex form f (x) = a(x - h)2+ k. (3pts) f ( x ) = 3 ( 6 * =h ) 2 + g c. Is the vertex a maximum or minimum point? (1pt) vertex is a minimum point 9 = 32 0 d. Algebraically (by hand) find the y-intercept. (2pts) 2 let x =0 F 10 ) = 3(0 ) - 6 (0 ) - 9 7 - int ( 0 ,- 9 ) 8 . Algebraically find the x-intercept(s). (5pts) let y = 0 X = 2, x = - 3 3 x 2 - 4 x - 9 = 0 ( 2, 0 ) ( - 3, 0 ) x 2 + 2x - 3 = 0 ( x 13 ) ( x- 21 = 0