(9%) Problem 10: A V = 102-V source is connected in series with an R = 1.1-kS resistor and an L = 34-H inductor and the current is allowed to reach maximum. At time t = 0 a switch is thrown that disconnects the voltage source, but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 55 % of its maximum value, the battery is reconnected into the circuit by reversing the switch. Dave, Ananya - ananya.dave@icloud.com @theexpertta.com - tracking id: 5188-2B-92-4C-BCA7-35199. In accordance with Expert TA's Terms of Service, copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. D A 50% Part (a) At what value of the time t, in milliseconds, does the current reach 79 % of its maximum? Grade Summary 1 = Deductions 0% Potential 100% sino tan Submissions cos JC 7 8 9 HOME Attempts remaining: 12 cotan() asin( acos() 5 6 (5% per attempt) 3 detailed view atan( acotan( sinhO cosho tanho cotanh() + END Degrees Radians BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback. 4 50% Part (b) How much energy, in millijoules, is supplied in total by the battery, both in initially bringing the current to maximum and in bringing the current back to the 79 % level from 55 %? Ignore energy dissipated in the resistor during those processes. All content @ 2022 Expert TA, LLC