Question: (9%) Problem 7: For the circuit shown: Vs = [1 72 V)Cos[(rs4a rad:s)t] R1 = 57. 7 E! R2 = 66.3 9 c = 9.

 (9%) Problem 7: For the circuit shown: Vs = [1 72V)Cos[(rs4a rad:"s)t] R1 = 57. 7 E! R2 = 66.3 9 c
= 9. 02 n: L : 74.2 mH. , 3 17% Part(5:) Determine the magnitude of the current through the inductor L (in

(9%) Problem 7: For the circuit shown: Vs = [1 72 V)Cos[(rs4a rad:"s)t] R1 = 57. 7 E! R2 = 66.3 9 c = 9. 02 n: L : 74.2 mH. , 3 17% Part (5:) Determine the magnitude of the current through the inductor L (in A). 9 a 17% Part (b) Determine the phase angle [in degrees) of the inductor current. 3 Q 17% Part (c) Determine the magnitude ofthe capacitor current (in A) 2 Q 17% Part ((1) Determine the phase angle [in degrees) of the capacitor current. 3 A 17% Part (9) Determine the magnitude ofthe source current (in A). - Q 17% Part (1') Determine the phase angle [in degrees) of the source current. 313: 7 (9%) Problem 8: For the circuit shown: Vs = (252 V)Cos[(2240 rad/s)t] R = 52.10 C = 8.07 UF Vs L = 89.3 mH. C R 4 50% Part (a) Determine the magnitude of the source current (in A). A 50% Part (b) Determine the phase angle (in degrees) of the source current

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