Question: 9. The eigenvalues of A = 3 -5 -3 are Al = -2, 12 = -2, A3 = 1. (a) (4 points) Find a basis

9. The eigenvalues of A = 3 -5 -3 are Al = -2, 12 = -2, A3 = 1. (a) (4 points) Find a basis for the eigenspace of 1 = -2. (b) (4 points) If the eigenspace of A = 1 has dimension 1, is A diagonalizable? Explain why or why not

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