Question: +9.33 x 10 C +91 Find the net force on 92. 0.180 m +4.22 x 10 C +92 0.230 m- -8.42 x 10 C

+9.33 x 10 C +91 Find the net force on 92. 0.180 m +4.22 x 10 C +92 0.230 m- -8.42 x 10 C 93 F = force exerted on q2 by 91 F3 = force exerted on 92 by 93 F = 10.9 N F3 = 6.04 N Remember: Forces pointing left are negative (-); forces pointing right are positive (+). EF=? N Enter

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