- 9-82 Engine oil at T = 60C is forced between two very large, stationary, parallel...
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- 9-82 Engine oil at T = 60C is forced between two very large, stationary, parallel flat plates separated by a thin gap height h = 2.5 mm (Fig. P9-82). The plate dimensions are L = 1.5 m and W = 0.75 m. The outlet pressure is atmos- pheric, and the inlet pressure is 1 atm gage pressure. Estimate the volume flow rate of oil. Also calculate the Reynolds num- ber of the oil flow, based on gap height h and average veloc- ity V. Is the flow laminar or turbulent? Answers: 9.10 10-4 m/s, 14.5, laminar Pout FIGURE P9-82 For fully develop flow in achannel u = I JP (y_hy), v=O zu dx Q = SuSA = 2 dx JP (y hy) wdy (yhy) Q- - JP hw Q. - 12 Pout-Pin L 1272-5103 = atm pressure in gage (N/m) (0-101300)=-67530 N/m 1.5 m *-67530*0.0025*0.75 = 9.\x104 m/s == Q hw -4 9.10010 = = 0.485 m/s 0.0025*0.75 Re-Puh = = u 8640-48515 * 0.0025 - laminar flow 72.5*103 =14.5 - 9-82 Engine oil at T = 60C is forced between two very large, stationary, parallel flat plates separated by a thin gap height h = 2.5 mm (Fig. P9-82). The plate dimensions are L = 1.5 m and W = 0.75 m. The outlet pressure is atmos- pheric, and the inlet pressure is 1 atm gage pressure. Estimate the volume flow rate of oil. Also calculate the Reynolds num- ber of the oil flow, based on gap height h and average veloc- ity V. Is the flow laminar or turbulent? Answers: 9.10 10-4 m/s, 14.5, laminar Pout FIGURE P9-82 For fully develop flow in achannel u = I JP (y_hy), v=O zu dx Q = SuSA = 2 dx JP (y hy) wdy (yhy) Q- - JP hw Q. - 12 Pout-Pin L 1272-5103 = atm pressure in gage (N/m) (0-101300)=-67530 N/m 1.5 m *-67530*0.0025*0.75 = 9.\x104 m/s == Q hw -4 9.10010 = = 0.485 m/s 0.0025*0.75 Re-Puh = = u 8640-48515 * 0.0025 - laminar flow 72.5*103 =14.5
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