Question: A 0 . 0 5 0 0 g positively charged ball with charge q = 6 . 2 5 C is resting on a flat,

A 0.0500 g positively charged ball with charge q =6.25 C is resting on a flat, frictionless, horizontal surface. For a time of t =0.0680 s, a constant electric field of magnitude E =6.00102 N/C is directed vertical to the ball, which makes the ball rise to a height of d. After this time, the electric field is turned off and the ball returns to the surface. Determine the height d.

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Given Mass of the ball m 00500 kg 500 g Charge of the ball q 625 C Time while the electric field is ... View full answer

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