A $0\mathrm{.}24-kg$ particle is moving with a velocity $v_1=[1\mathrm{.}6i+1\mathrm{.}0j+1\mathrm{.}5k]\frac{m}{s}$ at time $t_1=1\mathrm{.}3s.$ If the single force

$\{$:$1\mathrm{.}3t^2)j+3\mathrm{.}5k$ acts on the particle, determine its velocity $v_2$ at time $t_2=3\mathrm{.}8s.$

Answer:

$\frac{1}{2}$

$i+$

i

$]+$

i

k$]\frac{m}{s}$