A $0\mathrm{.}40-$kg particle is moving with a velocity $v_1=(2\mathrm{.}7i+1\mathrm{.}7j-3\mathrm{.}6k)\frac{m}{s}$ at time $t_1=2s.$ If the single force $F=[(6+9t)i+(7t^2-2)j+2k]N$ acts on the particle, determine its velocity $v_2$ at time $t_2=9s.$

Part $1$

Incorrect

Calculate the initial momentum of the $0\mathrm{.}40-kg$ particle.

Answer: $$ i$+$ i $$ j$+$ i k$)kg*\frac{m}{s}$