A 0.1276 g sample of an unknown monoprotic acid was dissolved in 25 mL of water and
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Question:
A 0.1276 g sample of an unknown monoprotic acid was dissolved in 25 mL of water and titrated with a 0.0633 M NaOH solution. The volume of the base required to reach the equivalent point was 18.4 mL. A) calculate the molar mass of the acid. B) after adding 10 mL of base, the measured pH was 5.87. What is the Ka value of the unknown acid?
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