a$)10111$ is the two's complement representation of: $($CLO $1\mathrm{.}1)$

i$.+22$

ii$.-10$

iii. $+9$

iv$.-22$

$v$:$-9$

b$)$ Converting $(1011011\mathrm{.}01)2$ to base $16$ yields which of the following results? $($CLO $1\mathrm{.}1)$

i$.5$ D $\mathrm{.}5$

ii$.$ AB$.5$

iii. $5$B$.4$

iv$.75\mathrm{.}4$

v$.5$B$.1$

c$)$ Simplification of the Boolean expression $(A+B{)}^{\text{'}}(C+D+E)+(A+B)(C+D+E)$ yields which of the following results? $($CLO $2\mathrm{.}1)$

i$.A+B$

ii$.,C+D+E$

iii. $A^{\text{'}}{B}^{\text{'}}{C}^{\text{'}}$

iv$.D^{\text{'}}{E}^{\text{'}}$

v$.$ None of the above

d$)$ Simplification of the Boolean expression $A^{\text{'}}BC+$ABC$+$ABCD$+$ABCDE$+$ABCDEF yields which of the following results? $($CLO $2\mathrm{.}1)$

i$.$ ABC

ii$.$ ABCDEF

iii. $A^{\text{'}}BC$

iv$.BC$

v$.A^{\text{'}}B$

e$)$ Given that $F=(A+B^{\text{'}}+C)(D+E),$ which of the following represents the only correct expression for $F^{\text{'}}($complement of $F)?($CLO $2\mathrm{.}1)$

i$.F^{\text{'}}=A^{\text{'}}B{C}^{\text{'}}+D^{\text{'}}+E^{\text{'}}$

ii$.F^{\text{'}}=A^{\text{'}}B{C}^{\text{'}}+D^{\text{'}}{E}^{\text{'}}$

iii. $F^{\text{'}}=(A^{\text{'}}+B+C^{\text{'}})(D^{\text{'}}+E^{\text{'}})$

iv$.F^{\text{'}}=A{B}^{\text{'}}C+DE$

v$.F^{\text{'}}=(A+B^{\text{'}}+C)(D^{\text{'}}+E^{\text{'}})$