A $10\mathrm{.}9-V$ battery, a $5\mathrm{.}10-$ resistor, and a $10\mathrm{.}5-H$ inductor are connected in series. After the current in the circuit has reached its maximum value, calculate the following.

$($a$)$ the power being supplied by the battery

$2318\mathrm{.}8\backslash$times W This is greater than the power that would be supplied if the circuit consisted of the battery and resistor alone. Can the inductor increase the amount of power taken from the battery?

$($b$)$ the power being delivered to the resistor

$2318\mathrm{.}8\backslash$times W You are correct that the power delivered to the resistor is equal to the power provided by the battery, but your value for this power is incorrect.

$($c$)$ the power being delivered to the inductor

$$

$0$ W You can determine the energy stored in the inductor from how much energy would be dissipated in a resistor if the battery were no longer in the circuit, so that the current decays back to zero. You can also find an equation for the stored energy.

$($d$)$ the energy stored in the magnetic field of the inductor

$$

$239870$

J

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