Question: A 1 2 . 9 6 g bullet is fired into a 5 . 0 0 0 kg ballistic pendulum suspended by 2 . 0

A 12.96 g bullet is fired into a 5.000 kg ballistic pendulum suspended by 2.000 m cords. When the bullet strikes the pendulum block it embeds into the block, making this an (elastic/inelastic) collision.
Upon impact the pendulum swings through an arc of 28.84.
a) The pendulum increased it's height by m, which corresponds to an increased gravitational potential energy of PEg = J.
b) This means the block/bullet combination had a total kinetic energy of KE = J at the bottom of the arc, at the moment the bullet was brought to rest in the block, which corresponds to a velocity of V = ms-1, and a total momentum of P = kgms-1, after the collision of the bullet with the pendulum block.
c) Since the pendulum block had a total momentum of Pblock = kgms-1 before the collision, the bullet by itself had a momentum of Pbullet = kgms-1 before the collision, which corresponds to a velocity of Vbullet = ms-1, to 3 significant digits only please.
d) A second rifle is brought in and fired at the same pendulum block. This time a 19.44 g bullet, with a pre-collision velocity of Vbullet-2=781 ms-1 embeds into the block, causing it to swing through an arc of .

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