Question: A ( 1 5 0 - mathrm { kg } ) block is sliding down a smooth inclined plane, as shown in

A \(150-\mathrm{kg}\) block is sliding down a smooth inclined plane, as shown in the figure. At the position indicated, the block has a velocity of \(3\mathrm{~m}/\mathrm{s}\) along the plane, and the attached spring (spring constant \(\mathrm{k}=25\mathrm{~N}/\mathrm{m}\)) is stretched by 0.3 m . Using the principle of work and energy, calculate the velocity of the block after it has moved 1.5 m further down the plane.
A \ ( 1 5 0 - \ mathrm { kg } \ ) block is

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