A $160-lb$ block is accelerated at $12f\frac{t}{s^2}$ by a horizontal force $F$ on a horizontal surface. If the coefficient of sliding friction between the block and surface is $=0\mathrm{.}7,$ the force $F$ is best given by

$($a$)308$ lb

$($b$)172$ lb

c$.112$ lb

d$.2030$ lb

$=160(9\mathrm{.}81)15$

$v=12$

$f=\mathrm{.}7$

$N=1570$

$\mathrm{.}9(1570)1099$

$F_N=F-UN1570-1099$

$F=1570(12)$

Please solve with detailed steps describing the proccess to solve. Thank you