A 1.00-cm-high object is placed 4.20 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. 9.1 position X Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm in front of the second lens height 2.2 X Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm