A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460

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A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate.

mass:

Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration.

[Na+]=

[NO−3]=

[Sr2+]=

[F−]=

Posted Date: Nov 08, 2021 12:34 PM

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A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460

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I Waite a balanced chenical equation Sr NO2 2NAF Sa Fg 2 NANO3 ... View the full answer

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