A $25-$kW$,250-$V d$.$c$.$ shunt generator has armature and field resistances of $0\mathrm{.}06$ ohms and $100$ ohm respectively. The total armature power developed when working as a motor taking $25$ kW input equals:

$($a$)26\mathrm{.}25$ kW

$($b$)23\mathrm{.}8$ kW

$($c$)25$ kW

$($d$)24\mathrm{.}4$ kW

Please provide the correct analysis, there has been previous answer for this, however, my understanding is that even though the question mentions it is a shunt generator I$($armature$)=$I$($line$)+$I$($field$),$ however it suddenly refers to when it "works as a motor taking $25$kW input", therefore it should be I$($armature$)=$I$($line$)-$I$($field$).$ Furthermore, since the question is asking what is the total armature power developed, should the formula just P$($armature$)=$ I$($armature$)*$Ea or Vt $-$ I$($armarure$)*$R$($armature$).$ Thank you for reading thus far and I hope you are able to assist me with this understanding...