A 25.0 kg asteroid initially at rest and located at 6.37 x 10¹⁰ m from the center of Earth accelerates toward Earth due to Earth's gravity. What is the speed of the asteroid (in km/s) when it strikes the surface of the Earth. (G= 6.67 x 10-11 m/kg-s², radius of Earth = 6.37 x 10⁶ m, mass of Earth = 5.97 x 10²⁴ kg, ) 

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To solve this problem we can use the concept of gravitational potential energy and kinetic energy to ... View the full answer