A 2-level Full.Factorial design with 4 quantitative factors A, B, C and D is created. 4...

 

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A 2-level Full.Factorial design with 4 quantitative factors A, B, C and D is created. 4 center points and no replicates are used. The results of the analysis are below. Analysis of Variance Source Model Linear A B C D 2-Way Interactions A B A'C A D B C B*D C'D Curvature Error Lack-of-Fit Pure Error Total DF 11 4 1 Adj ss 2802.20 2701.25 256.00 2304.00 20.25 121.00 1 1 1 6 93.75 1 4.00 1 2.25 1 0.00 1 6.25 1 81.00 1 0.25 1 7.20 8 34.75 5 6.00 3 28.75 19 2836.95 Adj ms 254.75 675.31 256.00 2304.00 20.25 121.00 15.62 4.00 2.25 0.00 6.25 81.00 0.25 7.20 4.34 1.20 9.58 F-Value P-Value 58.65 0.000 155.47 0.000 0.000 0.000 0.063 0.001 58.94 530.42 4.66 27.86 3.60 0.92 0.52 0.00 1.44 18.65 0.06 1.66 0.13 0.049 0.365 0.492 1.000 0.265 0.003 016 0.234 0.976 What can be concluded from the results table using a 5% significant level? A 2-level Full.Factorial design with 4 quantitative factors A, B, C and D is created. 4 center points and no replicates are used. The results of the analysis are below. Analysis of Variance Source Model Linear A B C D 2-Way Interactions A B A'C A D B C B*D C'D Curvature Error Lack-of-Fit Pure Error Total DF 11 4 1 Adj ss 2802.20 2701.25 256.00 2304.00 20.25 121.00 1 1 1 6 93.75 1 4.00 1 2.25 1 0.00 1 6.25 1 81.00 1 0.25 1 7.20 8 34.75 5 6.00 3 28.75 19 2836.95 Adj ms 254.75 675.31 256.00 2304.00 20.25 121.00 15.62 4.00 2.25 0.00 6.25 81.00 0.25 7.20 4.34 1.20 9.58 F-Value P-Value 58.65 0.000 155.47 0.000 0.000 0.000 0.063 0.001 58.94 530.42 4.66 27.86 3.60 0.92 0.52 0.00 1.44 18.65 0.06 1.66 0.13 0.049 0.365 0.492 1.000 0.265 0.003 016 0.234 0.976 What can be concluded from the results table using a 5% significant level?

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Answer From the results table several conclusions can be drawn at a 5 significance level 1 Overall M... View the full answer