A $3\mathrm{.}67g$ lead weight, initially at $12\mathrm{.}9C,$ is submerged in $8\mathrm{.}01g$ of water at $62\mathrm{.}9C,$ in an insulated container.

Part A

What is the final temperature of both substances at thermal equilibrium? The specific heat capacity for lead is $0\mathrm{.}128\frac{J}{g*C}$ and that for water is $4\mathrm{.}184\frac{J}{g*C}.$

Express your answer in degrees Celsius to three significant figures.