Question: A 4 . 1 0 0 - m - long quarter - circular gate of radius 2 m and of negligible weight is hinged about

A 4.100-m-long quarter-circular gate of radius 2 m and of negligible weight is hinged about its upper edge A, as shown in the figure. The gate controls the flow of water over the ledge at B, where the gate is pressed by a spring. Determine the minimum spring force required to keep the gate closed when the water level rises to A at the upper edge of the gate. Take the density of water to be 1,000kgm3.
The minimum spring force required to keep the gate closed is
kN .
Find the force applied by support BC to the gate AB. The width of the gate and support is 3 m and the weight of the gate is 1,600N. Take the density of water to be 1,000kgm3.
The force applied by support BC to gate AB is
N.
Gate AB(0.6-m0.9-m) is located at the bottom of a tank filled with methyl alcohol (SG=0.79) and hinged along its bottom edge A. Knowing that the weight of the gate is 320 N , determine the minimum force that must be applied to the cable (BCD) to open the gate. Take the density of water to be 1,000kgm3.
The minimum force that must be applied to the cable to open the gate is
N.
An open settling tank shown in the figure contains a liquid suspension, as shown in the figure. Determine the resultant force acting on the gate and its line of action if the liquid density is 870kgm3.
The resultant force acting on the gate is kN . The line of action of the force is m from the bottom of the tank. (Round the final answer to three decimal places.)
For non-symmetric immersed surfaces, the coordinate of the pressure center is not zero and can be either a positive or negative number. Derive an expression for x coordinate of the pressure center and determine the resultant force acting on the 0.7-m-high and 0.7-m-wide triangular gate shown in the figure and its line of action. Take the density of water to be 1,000kgm3. The distance d from the surface to the top of the gate is 0.310 m as shown in the figure.
The resultant force acting on the triangular gate is q, IN.
The line of action of the force is Im.(Round the final answer to three decimal places.)
A 4 . 1 0 0 - m - long quarter - circular gate of

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!