A $5\mathrm{.}8$kg block of wood resting on a platform was hit by a $0\mathrm{.}03$kg of bullet travelling upward with a speed of $751m/s.$ The bullet emerges from the block with a speed of $465\frac{}{}m/s.$ What is the height reached by the block relative to its initial position? Use $g=9\mathrm{.}8\frac{}{\mathrm{}}$m/s².

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The problem is a classic problem of conservation of momentum and energy Lets start by understanding the concept of momentum Momentum is the product of ... View the full answer