a. [ 5 points] Write the MIPS assembly code equivalent to the following HLL code.

Assume the variables A, B, and C are in $8, $9 and $10 respectively, and the variable ALLEQUAL is left in $11.

IF (A == B) AND (B == C)

ALLEQUAL = 1;

ELSE

ALLEQUAL= 0;

b. [5 points] Complete the following MIPS assembly code (or, you may write your own code), which is an assembly language version of the following java code segment(or, you may write your own code):

If (A[i] != A[i +1])

A[i] = 2 * A [i+1];

At the beginning of this code segment, the only values in registers are the base address of array A

in register $S0 and the value of i is in $S1.

sll $s1, $s1, 2

add $s0, $s0, $s1

lw $t1, 0($s0) # $t1 A[i]

lw $t2, 4($s0)

beq $t1, $t2, endIf

add $t2, $t2, $t2

sw $t2, 0($s0)

endif:

c.

.globl main

main:

addi $s0, $0, -5, # $s0 = x = -5

move $a0, $s0 # to pass the parameter

ja l ABS # call abs(x)

move $s0, $v0 # x = abs(x)

move $a0, $s0 # to print integer x

li $v0, 1

syscall

li $v0, 10 # to exit the program

syscall

ABS:

bgt $a0, $0, IF # if (x > 0) branch to label IF

sub $v0, $0, $a0 # else return -1 * x ( or 0 - x)

j ENDIF

IF:

move $v0, $a0 # return x

ENDIF:

jr $ra

[10 points] Complete the MIPS assembly language version of the given java code segment: The program converts a variable to its absolute value and display it on console.

Use $s0 for variable x.

main(String[] args) {

int x = -5;

x = abs(x);

System.out.println(x);

}

int abs(int x){

if (x > 0)

return x;

else

return (0 - x);

}