Question: A 5.00 kg block is released from rest on a ramp that is inclined at an angle of 60.0 below the horizontal. The initial position

A 5.00 kg block is released from rest on a ramp that is inclined at an angle of 60.0 below the horizontal. The initial position of the block is a vertical distance of 2.00 m above the bottom of the ramp. Part A Part complete If the speed of the block is 5.00 m/s when it reaches the bottom of the ramp, what was the work done on it by the friction force? Express your answer with the appropriate units. Wf = -35.5 J Previous Answers Correct Correct answer is shown. Your answer 35.6J was either rounded differently or used a different number of significant figures than required for this part. Part B Part complete If the angle of the ramp is changed but the block is released from a point that is still 2.00 m above the base of the ramp, both the magnitude of the friction force and the distance along the ramp that the block travels change. If the angle of the incline is changed to 50.0 , does the magnitude of the work done by the friction force increase or decrease compared to the value calculated in part A? The magnitude of the work done by friction decreases as decreases. The magnitude of the work done by friction increases as decreases. The magnitude of the work done by friction does not depend on . Previous Answers Correct Part C How much work is done by friction when the ramp angle is 50.0 ? Express your answer with the appropriate units. Activate to select the appropriates template from the following choice

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