Question: A 600 N force is exerted onto a spring, which is compressed a distance of 0.5 m as a result of the force. When

A 600 N force is exerted onto a spring, which is compressed a distance of 0.5 m as a result of the force. When the spring is released, block 1 (mass = 1 kg) accelerates across the frictionless surface and collides with block 2 (mass = 2 kg), which is initially at rest. Block 1 immediately comes to a rest after the collision. Block 2 travels along the smooth track eventually launching at a 30 angle above the horizontal. Three different height measurements are provided for your reference below. 1 2 1m 4m Ground (a). Calculate the velocity of block 2 immediately after the collision. Show all work for credit. 30 1m (b). Calculate the launch velocity of block 2 at the end of the track. Show all work for credit. (c). Calculate the horizontal projectile distance the block travels before striking the ground. Show all work for credit. (d). Calculate the vertical component of the impulse exerted by the ground onto block 2 once it strikes the ground.
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
