Question: (a) Assuming we are using the following hash function h(key)=key%10 with quadratic probing to resolve collisions, show where the key value 24 would be placed

 (a) Assuming we are using the following hash function h(key)=key%10 with

(a) Assuming we are using the following hash function h(key)=key%10 with quadratic probing to resolve collisions, show where the key value 24 would be placed in the table? (b) Assuming we are using the following hash function h(key)=key%10 with double hashing (random rehash) to resolve collisions show where the key value 24 would be placed in the table? Assume the random rehash function is of the form h(key)=( key +ic( key )) %10 where c( key )= key %7

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