a) b) A force of F= 500 N is applied to the end of the cable...
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a) b) A force of F= 500 N is applied to the end of the cable that is attached to block A as shown in Figure Q2(a). The masses of block A and block B are 200 kg and 400 kg respectively. The coefficient of friction between the blocks is 0.3 while the coefficient of friction between B and the floor is 0.2. Determine; i) if the system would be in equilibrium for P 2500 N. the maximum force P for which the system is in equilibrium. (CO2/PO2/WK3)[C4](13 marks) Using the result in part (a) and the system is in equilibrium, determine the mass of block A if the direction of force F is increased to 45. Briefly explain the result. F 30 B A Figure Q2(a) (CO3/PO3/WK3)[C5](7 marks) a) b) A force of F= 500 N is applied to the end of the cable that is attached to block A as shown in Figure Q2(a). The masses of block A and block B are 200 kg and 400 kg respectively. The coefficient of friction between the blocks is 0.3 while the coefficient of friction between B and the floor is 0.2. Determine; i) if the system would be in equilibrium for P 2500 N. the maximum force P for which the system is in equilibrium. (CO2/PO2/WK3)[C4](13 marks) Using the result in part (a) and the system is in equilibrium, determine the mass of block A if the direction of force F is increased to 45. Briefly explain the result. F 30 B A Figure Q2(a) (CO3/PO3/WK3)[C5](7 marks)
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The image youve provided presents a physics problem involving two blocks A and B with an applied force F and another force P acting horizontally on block B The masses of the blocks and the coefficients of friction between the blocks as well as between block B and the floor are given Lets resolve part a of the problem step by step i To check if the system will be in equilibrium with P 2500 N we need to calculate the maximum possible frictional force that can act on block B due to the applied force F on block A The force F can be broken down into two components the horizontal component Fcos30 that will pull block B and the vertical component Fsin30 that will add to the normal reaction on block A The maximum friction force between block A and block B fABmax can be calculated as fABmax coefficient ... View the full answer
Related Book For
Vector Mechanics for Engineers Statics and Dynamics
ISBN: 978-0073212227
8th Edition
Authors: Ferdinand Beer, E. Russell Johnston, Jr., Elliot Eisenberg, William Clausen, David Mazurek, Phillip Cornwell
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