$A={\displaystyle \underset{?}{\overset{?}{}}}\frac{}{b}ar(r)L$

$=2[0\mathrm{.}09(0\mathrm{.}05)+0\mathrm{.}06(0\mathrm{.}1)+0\mathrm{.}03(0\mathrm{.}03)]$

$=71\mathrm{.}6(10{)}^{-3}{m}^2$

Michigan Technological University

Manufacturing and Mechanical

$1885$

Engineering Technology

Worksheet$/$homework

$9-99$ Determine the approximate amount of aluminum necessary to make the funnel. It consists of a full circular part having a thickness of $2$ mm $.$