Question: A B sin 90 0 sin50 B cos32 sin 90 0 A cos 50 cos 40 sin32 sin5C = A cos32 = A sin(90 +0)

sin5C = A cos32 = A sin(90 +0) . cos cos40' su-,32'

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A B sin 90 0 sin50 B cos32 sin 90 0 A cos 50 cos 40 sin32

sin5C = A cos32 = A sin(90 +0) . cos cos40' su-,32'

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