A balanced, three$-$phase, $550V,$ABC supply is connected to an unbalanced, $3$ W $[$i$.$e$.$ the neutral of the supply $(N)$ is not connected to the neutral of this load $(O)$ wye$-$connected, three$-$phase load with $\frac{?}{\text{b}\text{a}\text{r}}(z{)}_{AO}=j2\frac{,}{b}ar(Z{)}_{BO}=-j4\frac{,}{b}ar(Z{)}_{CO}=6$ and an unbalanced, delta$-$connected, three$-$phase load with $\frac{?}{\text{b}\text{a}\text{r}}(Z{)}_{AB}=j5\frac{,}{b}ar(Z{)}_{BC}=-j7\frac{,}{b}ar(Z{)}_{CA}=9.$

a$.$ use wye$-$delta transformation to convert the wye$-$connected load to an equivalent delta$-$connected load

b$.$ determine the total parallel impedance for each section of the total deltaconnected load

c$.$ briefly explain WHY a delta$-$wye transformation wouldn't be employed

Draw the schematic diagram showing the proper connection of two single$-$phase wattmeters being used to measure the total three$-$phase power in the circuit of question $1$ from assignment $8.$ Show the connections and polarity markings in such a way that the current coil of wattmeter $1($W$1)$ is in phase B and the current coil of wattmeter $2($W$2)$ is in phase $C.$ Using an ABC sequence and $\frac{?}{\text{b}\text{a}\text{r}}(V{)}_{CA}$ as reference, show the calculations required to predict the readings for each wattmeter and calculate the power factor angle from your predictions.

Draw the schematic diagram showing the proper connection of two single$-$phase wattmeters being used to measure the total three$-$phase power in the circuit of question $3$ from assignment $8.$ Show the connections and polarity markings in such a way that the current coil of wattmeter $1($W$1)$ is in phase $C$ and the current coil of wattmeter $2($W$2)$ is in phase $A.$ Using a CBA sequence and $\frac{?}{\text{b}\text{a}\text{r}}(V{)}_{CN}$ as reference, show the calculations required to predict the readings for each wattmeter and calculate the power factor angle from your predictions.

Could I get help with #$1-3$ please? I$\text{'}$m not sure if I$\text{'}$m doing it correct. Thank you.