A Balloon Is Rising Vertically Above A Level, Straight Road At A Constant Rate Of 4 Ft / Sec. Just When The Balloon Is 80 Ft Above The Ground, A Bicycle Moving At A Constant Rate Of 13 Ft / Sec Passes Under It. How Fast Is The Distance S(T) Between The Bicycle And Balloon Increasing 6 Seconds Later? S(T) Is Increasing By Ft/Sec. (Simplify Your Answer.)

 

A balloon is rising vertically above a level, straight road at a constant rate of 4 ft/sec. Just when the balloon is 80 ft above the ground, a bicycle moving at a constant rate of 13 ft / sec passes under it. How fast is the distance s(t) between the bicycle and balloon increasing 6 seconds later? y(t) s(t) 0 x(t) x