A bar AB with solid circular cross section is loaded by a distributed torque of constant...

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A bar AB with solid circular cross section is loaded by a distributed torque of constant intensity, t, per unit distance (see figure). The polar moment of the area is a constant, Ip, and the shear modulus is a constant, G. The total length of the bar is L. Determine the angle of twist at the end of the bar. cc c c c c ce B Problems (from Gere and Goodno, 9th edition): 1.7-1 A high-strength steel bar used in a large crane has a diameter d= 2.00 in. (see figure). The steel has a modulus of elasticity E = 29 x 106 psi and Poisson's ratio is v = 0.29. Because of clearance requirements, the diameter of the bar is limited to 2.001 in. when it is compressed by axial forces. What is the largest compressive load Pmax that is permitted? PROBLEM 1.7-1 1d axial Perpendicular EOM Global FBD Cut FBD P Elateral = -J Eaxtal EFx =0 Ad -Pmak antal JEE akhal Jacial - A =- Janial SFX=0 SE=0 Eaxlal= hoat E Easial - EA -N-P=0 0.001 ( == -0.29 P-P=0 0=0 N=-P LEA 0.001 = +0.29 Pmax (29x10 psi (#1 (2in)) Lmax = 157,080 165 157,080 165 or 157 kips 1000 165= | Kip A bar AB with solid circular cross section is loaded by a distributed torque of constant intensity, t, per unit distance (see figure). The polar moment of the area is a constant, Ip, and the shear modulus is a constant, G. The total length of the bar is L. Determine the angle of twist at the end of the bar. cc c c c c ce B Problems (from Gere and Goodno, 9th edition): 1.7-1 A high-strength steel bar used in a large crane has a diameter d= 2.00 in. (see figure). The steel has a modulus of elasticity E = 29 x 106 psi and Poisson's ratio is v = 0.29. Because of clearance requirements, the diameter of the bar is limited to 2.001 in. when it is compressed by axial forces. What is the largest compressive load Pmax that is permitted? PROBLEM 1.7-1 1d axial Perpendicular EOM Global FBD Cut FBD P Elateral = -J Eaxtal EFx =0 Ad -Pmak antal JEE akhal Jacial - A =- Janial SFX=0 SE=0 Eaxlal= hoat E Easial - EA -N-P=0 0.001 ( == -0.29 P-P=0 0=0 N=-P LEA 0.001 = +0.29 Pmax (29x10 psi (#1 (2in)) Lmax = 157,080 165 157,080 165 or 157 kips 1000 165= | Kip