Question: A baseball player's batting average is 0.348, which can be interpreted as the probability that he got a hit each time at bat. Thus, the

A baseball player's batting average is 0.348, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is

1−0.348=0.652. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits?

What expression can be used to calculate the probability? 4 OA. [2]

What expression can be used to calculate the probability? 4 OA. [2] (0.348) (0.652) B. 4 [2] 10 O D. (0.348 +0.652) 4 Oc. [2] (0.348)4 (0.652) 6 [8] (0.3 4 (0.348)4 (0.652)4 The probability that the player had 2 hits in 4 at-bats is (Round to three decimal places as needed.)

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