Question: A basketball player ( m = 9 0 kg ) lands on the gym floor from a lay - up jump with a initial impact

A basketball player (m =90 kg) lands on the gym floor from a lay-up jump with a initial impact velocity of v =4 x -5 y (m/s). Their landing takes 0.3 seconds with a constant ground reaction force to dissipate the vertical momentum. The coefficient of static friction is equal to 0.6.
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Question 11 pts
What is the vertical component of the ground reaction force during the landing?
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Question 21 pts
What is the horizontal component of the ground reaction force during the landing if the horizontal momentum were to be dissipated also over 0.3 seconds and without slip?
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Question 31 pts
What is the maximum static friction for the landing given the calculated vertical ground reaction force?
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Question 41 pts
What is the instantaneous power at impact of the vertical ground reaction force (in Watts)?

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