A bead with a hole through it slides on a wire track. The wire is threaded...

 

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A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h= 3.20R. A R (a) What is its speed at point O? (Use the following as necessary: the acceleration due to gravity g, and R.) v = V24R (b) How large is the normal force on the bead at point A if its mass is 5.50 grams? magnitude 0.077 direction downward Need Help? Read It Master It

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A By Conservation of energy mgh ... View the full answer