Question: A block m 1 rests on a surface. A second block m 2 sits on top of the first block. A horizontal force F applied

A block m1 rests on a surface. A second block m2 sits on top of the first block. A horizontal force
F
applied to the bottom block pulls both blocks at constant velocity. Here m1= m2= m.
(a)
What is the normal force exerted by the surface on the bottom block? (Use the following as necessary: m and g as necessary.)
N1=
(b)
What is the normal force exerted by the bottom block on m2?(Use the following as necessary: m and g as necessary.)
N2=
(c)
How would your answers to parts (a) and (b) change if m1=6m and m2= m?
N1=5mg, N2=4.5mg
N1=3mg, N2=3mg
N1=7mg, N2= mg
N1=7mg, N2=6mg
(d)
How would your answers to parts (a) and (b) change if m1= m and m2=6m?
N1=7mg, N2= mg
N1=5mg, N2=4.5mg
N1=7mg, N2=6mg
N1=3mg, N2=3mg

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!