Question: A block with mass ( m = 5 . 0 0 mathrm { ~kg } ) slides down a surface inclined

A block with mass \( m=5.00\mathrm{~kg}\) slides down a surface inclined \(36.9^{\circ}\) to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at \( O \). The flywheel has mass 8.16 kg and moment of inertia \(0.500\mathrm{~kg}\cdot \mathrm{~m}^{2}\) with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.350 m from that axis.
Part A
What is the acceleration of the block down the plane?
Express your answer in meters per second squared.
\([\)
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Correct answer is shown. Your answer \(2.15\mathrm{~m}/\mathrm{s}^{2}\) was either rounded differently or used a different number of significant figures than required for this part.
Part B
What is the tension in the string?
Express your answer in newtons.
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A block with mass \ ( m = 5 . 0 0 \ mathrm { ~kg

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