A box having a mass of M is resting on another box (50 kg) that is...

  

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A box having a mass of M is resting on another box (50 kg) that is placed on an inclined surface. The coefficient of friction between the lower box and the inclined surface is on μ₁ = 0.3 and between the boxes ₂ = 0.25. The roller is frictionless and the mass of the rope is ignored. Determine the minimum of the mass M such that the system is still at rest. Let's have F= 250 N, G = 350 N and a = 35°. The mass M, when the upper box is about to move upwards = kg The mass M, when the upper box is about to move downwards = kg The mass M, when both boxes are about to move upwards = kg The mass M, when both boxes are about to move downwards = kg The minimum of the mass M such that the system is still at rest = kg F M 50 kg a G A box having a mass of M is resting on another box (50 kg) that is placed on an inclined surface. The coefficient of friction between the lower box and the inclined surface is on μ₁ = 0.3 and between the boxes ₂ = 0.25. The roller is frictionless and the mass of the rope is ignored. Determine the minimum of the mass M such that the system is still at rest. Let's have F= 250 N, G = 350 N and a = 35°. The mass M, when the upper box is about to move upwards = kg The mass M, when the upper box is about to move downwards = kg The mass M, when both boxes are about to move upwards = kg The mass M, when both boxes are about to move downwards = kg The minimum of the mass M such that the system is still at rest = kg F M 50 kg a G

Answer rating: 100% (QA)

Solution To solve this problem we need to find the minimum value of M such that the system is still at rest We can do this by analyzing the forces acting on the system and finding the critical value o... View the full answer