A C Differentiate the function (a . vt + b) . to with respect to t. 6 at (( a . vt + 6) . to ) = a. (n+ ? ). to - 2 + n . 6 . tn - 1 ((a . Vt + b ) . to ) = d dt ( a . Vt + 6 ) . to + ( a . VE + b ) . - dor ( th ) product rule + (g(t) . h(t)) = g' (t) . h(t) + g(t) . h'(t) a 2 . Vt the + n . th -1 . ( a . VE + 6 ) factors derived separately with sum rule and power rule = a . n + . the - 2 + n . b . tn - 1 simplified A good alternative is to rewrite the function first as the sum of two powers: a . th+ 2 + b . to and then to differentiate this using the sum rule and the rule of power