A Carnot cycle operates between two heat sources at temperatures T$1$ and T$2($T$1>$ T$2).$

However, the temperature of the working fluid is $1$ and $2,$ where $1<$ T$1$ and $2>$ T$2.$ If

T$1=(1+$kQ$1)$ and T $=(2-$kQ$2)$ where, Q$1$ and Q$2$ are the amounts of heat extracted

from the hot source and rejected to sink$,$ respectively, and K is a constant. Show that the

efficiency of the engine is given by $=1-$ T$2/($T$1-2$KQ$1)$