A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of ${10}^{-5}{H}^{+}$ions. The emf of the cell is $0\mathrm{.}118V$ at $298K.$ Calculate the concentration of the $H^{+}$ions at the positive electrode.

Ans: The cell reaction can be represented as$,$

$Pt|H^{\text{'}}({10}^{5}M)1$atm $|H^{-}(aM)|1$atm $|Pt$