Question: A cell receives nutrients through its surface and its surface area is proportional to the two thirds power of its weight Therefore if w t

A cell receives nutrients through its surface and its surface area

A cell receives nutrients through its surface and its surface area is proportional to the two thirds power of its weight Therefore if w t is the cell s weight at time t then w t satisfies w aw2 3 where a is a positive constant t Solve this differential equation with the initial condition w 0 7 initial weight 7 units w t 3 at 7 X

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