A certain right triangle has area 24 in.". One leg of the triangle measures 4 in. less than the hypotenuse. Let x represent the length of the hypotenuse. Complete parts a) through d). a) Express the length of the leg mentioned above in terms of x. Give the domain of x. The length of one leg is a =] The domain of x is . (Type your answer in interval notation.) b) Express the length of the other leg in terms of x. The length of the other leg is b =] c) Write an equation based on the triangle having an area of 24 in and the information determined thus far. Square both sides and then write the equation with one side as a polynomial with coefficients, in descending powers, and the other side equal to 0. Divide out any common factors to find the most simplified form. =0 (Simplify your answer. Do not factor.) d) Solve the equation in part (c) graphically. Find the lengths of the three sides of the triangle. The legs of the triangle are a = in. and b= in., and the hypotenuse is c= |in