Question: A circular foundation rests on a floor whose friction angle is 2 5 degrees, the specific weight of the supporting floor is 1 3 0

A circular foundation rests on a floor whose friction angle is 25 degrees, the specific weight of the supporting floor is 130 pounds/cubic foot, the groundwater level is 8 feet below the displacement level of the foundation, ground cohesion is 380 pounds/square foot, the floor of over load has a thickness of 7 feet.
It is requested:
For the circular foundation whose diameter is 7 feet, determine the permissible load using a safety factor of four by the method of terzaghi general fault.
Suppose that the water table reaches the level of the ground, what would be the resistance of the support floor?

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