Question: A circular sedimentation basin is 1 3 3 . 2 ft in diameter and 1 2 ft in depth with the sludge zone comprising the

A circular sedimentation basin is 133.2 ft in diameter and 12 ft in depth with the sludge zone comprising the bottom two feet of the basin. The flow rate is 20 MGD and the particles in the feed stream entering the basin have a particle settling velocity distribution function (pdf) as shown in Figure 1-1 and given by the following equation:
F'(vs)=0.2-0.02vs,(hrft)
where vs is in units of fthr. Assume for this problem that the basin overflow rate is equal to the theoretical overflow rate.
Figure 1-1.
a) Determine the theoretical overflow rate, vo,theory(fthr) for the sedimentation basin.
b) What is the detention time of the basin (hr)?
c) Develop an analytical expression for the cumulative settling velocity distribution function, F(vs) as a function of vs.
d) Draw the cumulative particle velocity distribution function, F(vs) vs.vs, for the particles entering the basin for 0.
e
A circular sedimentation basin is 1 3 3 . 2 ft in

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