A clock is constructed so that it keeps perfect time when its simple pendulum has a period of

$1\mathrm{.}000$

s at locations where

$$

$=$

$9\mathrm{.}800$

$$

m

$$

s

$2$

$.$ The pendulum bob has length

$$

$=$

$0\mathrm{.}2482$

m$,$ and instead of keeping perfect time, the clock runs slow by

$1\mathrm{.}500$

minutes per day.

What is the free$-$fall acceleration at the clock$$s location?

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What length of pendulum bob is required for the clock to keep perfect time?