A coarse-grained fill was placed on saturated clay. A noncircular slip surface was assumed, as shown...
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A coarse-grained fill was placed on saturated clay. A noncircular slip surface was assumed, as shown in the figure below. Determine the factor of safety of the slope using Bishop's method. Perform the calculations manually (with a spreadsheet or hand-drawn table). O Hint: use a minimum of 4 slices O Hint: the groundwater level is below the assumed slip surface. 5 m 2 m 459 2 m- 2 3 45° Assumed failure surface 59.9⁰ -3.5 m2 m 2.9 m Soil 2 Y = 17 kN/m³ $ = 33° Soil 1 Y = 18 kN/m³ $ = 29⁰ A coarse-grained fill was placed on saturated clay. A noncircular slip surface was assumed, as shown in the figure below. Determine the factor of safety of the slope using Bishop's method. Perform the calculations manually (with a spreadsheet or hand-drawn table). O Hint: use a minimum of 4 slices O Hint: the groundwater level is below the assumed slip surface. 5 m 2 m 459 2 m- 2 3 45° Assumed failure surface 59.9⁰ -3.5 m2 m 2.9 m Soil 2 Y = 17 kN/m³ $ = 33° Soil 1 Y = 18 kN/m³ $ = 29⁰ A coarse-grained fill was placed on saturated clay. A noncircular slip surface was assumed, as shown in the figure below. Determine the factor of safety of the slope using Bishop's method. Perform the calculations manually (with a spreadsheet or hand-drawn table). O Hint: use a minimum of 4 slices O Hint: the groundwater level is below the assumed slip surface. 5 m 2 m 459 2 m- 2 3 45° Assumed failure surface 59.9⁰ -3.5 m2 m 2.9 m Soil 2 Y = 17 kN/m³ $ = 33° Soil 1 Y = 18 kN/m³ $ = 29⁰ A coarse-grained fill was placed on saturated clay. A noncircular slip surface was assumed, as shown in the figure below. Determine the factor of safety of the slope using Bishop's method. Perform the calculations manually (with a spreadsheet or hand-drawn table). O Hint: use a minimum of 4 slices O Hint: the groundwater level is below the assumed slip surface. 5 m 2 m 459 2 m- 2 3 45° Assumed failure surface 59.9⁰ -3.5 m2 m 2.9 m Soil 2 Y = 17 kN/m³ $ = 33° Soil 1 Y = 18 kN/m³ $ = 29⁰
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