A coil of $12$ Omega resistance is in parallel with a coil of $25$ Omega resistance. This combination is connected in series with a third coil of $8$ Omega resistance. If the whole circuit is connected across a battery having an e$.$m$.$f$.$ of $10$ V and an internal resistance of $2$ Omega $,$ calculate:

 $($a$)$ the terminal voltage of the battery and

 $($b$)$ the power in the $12$ Omega coil. 

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To solve this problem we can start by first finding the equivalent resistance for the parallel combi... View the full answer