A comet has a period of orbit equal to $56\mathrm{.}8$ years. If the mean radius of orbit for this comet is $42\mathrm{.}0$ AU$,$ then, in scientific notation, the magnitude of Kepler's constant for the star about which this comet is in orbit is b $10$w y$2/$AU$3.$ The value of b is ?

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Keplens Third cave in which t2 T 568 Yea... View the full answer